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4

Overload protection is not

required for the flexible cord

from the luminaire supporting

coupler plug to the luminaire.

However, we need to

ensure that the conductors

concerned are large enough

to carry any fault currents

without damage until the

overcurrent device operates.

This section describes how

to make the necessary

calculation.

Q

How would you define

fault current?

A fault current is an

overcurrent caused by either

a short circuit (between

live

conductors) or an earth fault

(between a live conductor and

an exposed conductive part or

protective conductor).

Q

What do the Wiring

Regulations specify to protect

the flexible cord against fault

current?

If overload protection is not

required then a calculation

must be made. Regulation

434.5.2 provides an equation

for calculating the maximum

duration of the fault current,

but it is not immediately

apparent how to apply it. A

simple transposition, however,

gives us the equation.

I

2

t ≤ k

2

S

2

where I

2

t is proportional to

the thermal energy let through

the protective device;

k

2

S

2

indicates the thermal

capacity of the conductor.

If the conductor is not to be

damaged I

2

t must not exceed

k

2

S

2

;

t = the maximum fault

current duration in seconds

(disconnection time);

k = a factor taking account

of the resistivity, temperature

coefficient and heat capacity

of the conductor material,

and the initial and final

temperatures, derived from

BS 7671;

S = the nominal cross

sectional area of the

conductor in mm

2

;

I = the value of fault current

an amperes, expressed for ac

as the rms value, due account

being taken of the current

limiting effect of the circuit

impedances.

Note for very short duration

(less than 0.1 secs) and for

current limiting devices, I

2

t

must be designated by the

manufacturer’s data.

Q

How do I apply this

formula?

The simplest way of assessing

the degree of thermal

protection provided by an

overcurrent device is by

using the manufacturer’s I

2

t

characteristics. Calculate k

2

S

2

and

superimpose this value as a

horizontal line on the graph

Fault current protection

Figure 1: Assessing protection using the manufacturer's data

I

2

t(A

2

s)

5625

PFC(A)

0091

021

I

2

t characteristic Hager 16 A

type C circuit breaker to

BS EN 60898 (MCB)

Area above red

line indicates

conductor is not

protected

Area below red

line indicates

conductor is

protected

85°C pvc flexible cord

with 0.75 mm

2

conductors

k

2

S

2

= 100

2

x 0.75

2

= 5625

A

2

s

Minimum fault current for

thermal protection of

conductor. This value would

be derived at the furthest

LSC i.e. at the remote end of

the circuit and flexible cord

Maximum fault current for

thermal protection of

conductor. This value

would be derived at the

LSC closest to the origin

of the circuit