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56

MR

medium rating busbar

determining the operating current of a busbar

In order to determine the correct busbar rating, the current must be

established using the following criteria :

type of load inputs – three phase or single-phase

type of circuit input – from one end, from both ends, central input, etc.

nominal input voltage

number, power and cos

j

of loads which are to be fed by the busbar

load diversity factor

load use nominal factor

assumed short circuit current at the input point

room temperature

type of busbar installation (edgeways, flat or vertical)

When using a three phase power supply, the operating current is

determined by the following formula :

Where :

I

b

operating current (A)

a

load diversity factor (.)

b

load use factor (.)

d

feed factor (.)

P

TOT

sum of the total active power of installed loads (W)

Ue

operating voltage (V)

cos

j

medium

average load power factor (.)

The ‘d’ input factor has a value of 1 when the busbar is fed from one

end only. The value is if fed from the centre or if it is fed from

each end

Once the operating current has been determined, choose the busbar

with a rated current immediately higher than the one calculated

All Zucchini products have been designed and tested for an average

room temperature of 40°C; should they be installed in rooms with

average daily temperatures different from 40°C, the rated current of the

busbar should be multiplied by a k1 factor that is greater than the unit

for temperatures lower than 40°C, and lower than the unit if the room

temperature is higher than 40°C

Finally, the following should be considered for the most appropriate

busbar choice :

where I

nt

represents the maximum current loaded by a busbar for an

indefinite time at the specified room temperature

I

b

= PTOT •

a

b

• d (A)

3 • Ue • cos

j

medium

I

nt

I

b

I

nt

= k

1

• I

n

Voltage drop

If the length of the line is particularly long (>100m) it is necessary to check

the voltage drop (hereinafter specified as v.d.). If the installation is a three

phase system and the power factor is not lower than cosφ = 0.7 the v.d.

may be calculated with the coefficients of the voltage drop specified in the

technical data table.

Short circuit current

The short circuit current value I

CW

that can be supported by Zucchini busbar

trunking systems allows for both electrodynamic stress and thermal energy

dissipated during the fault

The busbars must be able to sustain the short circuit current for the entire

duration of the fault – i.e. for the time required for the protective device (circuit

breaker) to start operating, cutting off the metal continuity and extinguishing

the electric arc

Joule effect losses

Losses due to the Joule effect are essentially caused by the electrical

resistance of the busbar. Lost energy is transformed into heat and

contributes to the heating of the conduit

Three phase rating

Single phase rating

1

/

2

P = 3 • R

t

• I

b

2

• 10

-3

(W/m)

P = 2 • R

t

• I

b

2

• 10

-3

(W/m)

k

I

b

L

v% = b

• 100

Vn

Defined :

I

b

= the current that supplies the busbar (A)

Vn

= the voltage power supply of the busbar (V)

L

= the length of the busbar (m)

v%

= the voltage drop percentage

b

= the distribution factor of the current (.)

k

= corresponding voltage drop factor

a cos

j

(V/m/A) (see technical data table, p. 52-55)

The current distribution factor “b” depends on how the

circuit is fed and on the distribution of the electric loads

along the busbar :

b = 2

Supplies at one end and load

at the end of the line

b = 1

Supplies at one end and with

load evenly distributed

b = 0·5

Supplies at both ends and with

load evenly distributed

b = 0·5

Central supply with loads

at both ends

b = 0·25

Central supply with load

distributed evenly

Example :

MR 400 A Al for riser mains feed

I

b

= 315 A operating current

b = 1

= supply from one end

k = 179

= see technical data table, p. 52-55

Cos

j

= 0·85

L

= 30 m line length

Vn

= 400 V operating voltage

I

b

L

I

b

I

b

L

I

b

I

b

L

I

b

L

I

b

2

I

b

2

179 • 10

-6

• 315 • 30

v% = 1x

x100 = 0·42%

400

Room

15 20 25 30

35 40 45

50 55 60

temperature (°C)

k, thermal correction

1·15 1·12 1·08 1·05 1·025 1 0·975 0·95 0·93 0·89

factor (.)